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1352442017 is a prime number
BaseRepresentation
bin101000010011100…
…1010000010100001
310111020212011200002
41100213022002201
510232211121032
6342111305345
745341365433
oct12047120241
93436764602
101352442017
11634466783
12318b1b255
13187269a64
14cb892653
157daed862
hex509ca0a1

1352442017 has 2 divisors, whose sum is σ = 1352442018. Its totient is φ = 1352442016.

The previous prime is 1352441971. The next prime is 1352442037. The reversal of 1352442017 is 7102442531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1327800721 + 24641296 = 36439^2 + 4964^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1352442017 is a prime.

It is not a weakly prime, because it can be changed into another prime (1352442037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676221008 + 676221009.

It is an arithmetic number, because the mean of its divisors is an integer number (676221009).

Almost surely, 21352442017 is an apocalyptic number.

It is an amenable number.

1352442017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1352442017 is an equidigital number, since it uses as much as digits as its factorization.

1352442017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6720, while the sum is 29.

The square root of 1352442017 is about 36775.5627693173. The cubic root of 1352442017 is about 1105.8754531787.

Adding to 1352442017 its reverse (7102442531), we get a palindrome (8454884548).

The spelling of 1352442017 in words is "one billion, three hundred fifty-two million, four hundred forty-two thousand, seventeen".