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1343543351 is a prime number
BaseRepresentation
bin101000000010100…
…1101100000110111
310110122010001222212
41100011031200313
510222421341401
6341152444035
745202634003
oct12005154067
93418101885
101343543351
1162a439007
12315b4961b
13185472587
14ca617703
157ce41dbb
hex5014d837

1343543351 has 2 divisors, whose sum is σ = 1343543352. Its totient is φ = 1343543350.

The previous prime is 1343543329. The next prime is 1343543353. The reversal of 1343543351 is 1533453431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1343543351 - 222 = 1339349047 is a prime.

Together with 1343543353, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343543353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671771675 + 671771676.

It is an arithmetic number, because the mean of its divisors is an integer number (671771676).

Almost surely, 21343543351 is an apocalyptic number.

1343543351 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343543351 is an equidigital number, since it uses as much as digits as its factorization.

1343543351 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 32400, while the sum is 32.

The square root of 1343543351 is about 36654.3769691970. The cubic root of 1343543351 is about 1103.4446702866. Note that the first 3 decimals are identical.

Adding to 1343543351 its reverse (1533453431), we get a palindrome (2876996782).

The spelling of 1343543351 in words is "one billion, three hundred forty-three million, five hundred forty-three thousand, three hundred fifty-one".