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134115433 = 1919735831
BaseRepresentation
bin1111111111001…
…11000001101001
3100100100202210021
413333213001221
5233313143213
621150320441
73215651044
oct777470151
9310322707
10134115433
1169782a01
1238ab9121
1321a29a5a
1413b51c5b
15bb92d8d
hex7fe7069

134115433 has 8 divisors (see below), whose sum is σ = 141894720. Its totient is φ = 126408240.

The previous prime is 134115413. The next prime is 134115479. The reversal of 134115433 is 334511431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134115433 - 221 = 132018281 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134115398 and 134115407.

It is not an unprimeable number, because it can be changed into a prime (134115413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14173 + ... + 21658.

It is an arithmetic number, because the mean of its divisors is an integer number (17736840).

Almost surely, 2134115433 is an apocalyptic number.

It is an amenable number.

134115433 is a deficient number, since it is larger than the sum of its proper divisors (7779287).

134115433 is a wasteful number, since it uses less digits than its factorization.

134115433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36047.

The product of its digits is 2160, while the sum is 25.

The square root of 134115433 is about 11580.8217756772. The cubic root of 134115433 is about 511.8698921213.

Adding to 134115433 its reverse (334511431), we get a palindrome (468626864).

The spelling of 134115433 in words is "one hundred thirty-four million, one hundred fifteen thousand, four hundred thirty-three".

Divisors: 1 19 197 3743 35831 680789 7058707 134115433