Base | Representation |
---|---|
bin | 110011001011… |
… | …001010001101 |
3 | 221020112222211 |
4 | 303023022031 |
5 | 11413240203 |
6 | 1155310421 |
7 | 222011641 |
oct | 63131215 |
9 | 27215884 |
10 | 13415053 |
11 | 7632a23 |
12 | 45ab411 |
13 | 2a19102 |
14 | 1ad2c21 |
15 | 129ec6d |
hex | ccb28d |
13415053 has 4 divisors (see below), whose sum is σ = 13777660. Its totient is φ = 13052448.
The previous prime is 13415047. The next prime is 13415071. The reversal of 13415053 is 35051431.
It is a happy number.
13415053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35051431 = 79 ⋅443689.
It can be written as a sum of positive squares in 2 ways, for example, as 7717284 + 5697769 = 2778^2 + 2387^2 .
It is a cyclic number.
It is not a de Polignac number, because 13415053 - 217 = 13283981 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13415093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181248 + ... + 181321.
It is an arithmetic number, because the mean of its divisors is an integer number (3444415).
Almost surely, 213415053 is an apocalyptic number.
It is an amenable number.
13415053 is a deficient number, since it is larger than the sum of its proper divisors (362607).
13415053 is an equidigital number, since it uses as much as digits as its factorization.
13415053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 362606.
The product of its (nonzero) digits is 900, while the sum is 22.
The square root of 13415053 is about 3662.6565495553. The cubic root of 13415053 is about 237.6096808267.
Adding to 13415053 its reverse (35051431), we get a palindrome (48466484).
It can be divided in two parts, 134 and 15053, that multiplied together give a palindrome (2017102).
The spelling of 13415053 in words is "thirteen million, four hundred fifteen thousand, fifty-three".
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