Base | Representation |
---|---|
bin | 100111111100001… |
… | …1110000101000011 |
3 | 10110101211101100102 |
4 | 1033320132011003 |
5 | 10221043001311 |
6 | 340553113015 |
7 | 45132353225 |
oct | 11770360503 |
9 | 3411741312 |
10 | 1340203331 |
11 | 628567665 |
12 | 3149b876b |
13 | 18487322c |
14 | c9dc8415 |
15 | 7c9d243b |
hex | 4fe1e143 |
1340203331 has 2 divisors, whose sum is σ = 1340203332. Its totient is φ = 1340203330.
The previous prime is 1340203309. The next prime is 1340203351. The reversal of 1340203331 is 1333020431.
It is an a-pointer prime, because the next prime (1340203351) can be obtained adding 1340203331 to its sum of digits (20).
It is a strong prime.
It is an emirp because it is prime and its reverse (1333020431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340203331 is a prime.
It is a super-2 number, since 2×13402033312 = 3592289936846991122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1340203301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670101665 + 670101666.
It is an arithmetic number, because the mean of its divisors is an integer number (670101666).
Almost surely, 21340203331 is an apocalyptic number.
1340203331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340203331 is an equidigital number, since it uses as much as digits as its factorization.
1340203331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 20.
The square root of 1340203331 is about 36608.7876199144. The cubic root of 1340203331 is about 1102.5295315883.
Adding to 1340203331 its reverse (1333020431), we get a palindrome (2673223762).
The spelling of 1340203331 in words is "one billion, three hundred forty million, two hundred three thousand, three hundred thirty-one".
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