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134014211 = 180174411
BaseRepresentation
bin1111111110011…
…10010100000011
3100100011121221022
413333032110003
5233301423321
621144220055
73215046662
oct777162403
9310147838
10134014211
1169713951
1238a6a62b
13219c2966
1413b26dd9
15bb72dab
hex7fce503

134014211 has 4 divisors (see below), whose sum is σ = 134090424. Its totient is φ = 133938000.

The previous prime is 134014159. The next prime is 134014219. The reversal of 134014211 is 112410431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134014211 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134014211.

It is not an unprimeable number, because it can be changed into a prime (134014219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35405 + ... + 39006.

It is an arithmetic number, because the mean of its divisors is an integer number (33522606).

Almost surely, 2134014211 is an apocalyptic number.

134014211 is a deficient number, since it is larger than the sum of its proper divisors (76213).

134014211 is an equidigital number, since it uses as much as digits as its factorization.

134014211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76212.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 134014211 is about 11576.4507082266. The cubic root of 134014211 is about 511.7410838415.

Adding to 134014211 its reverse (112410431), we get a palindrome (246424642).

It can be divided in two parts, 1340 and 14211, that added together give a palindrome (15551).

The spelling of 134014211 in words is "one hundred thirty-four million, fourteen thousand, two hundred eleven".

Divisors: 1 1801 74411 134014211