13330113 has 4 divisors (see below), whose sum is σ = 17773488. Its totient is φ = 8886740.

The previous prime is 13330099. The next prime is 13330117. The reversal of 13330113 is 31103331.

13330113 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13330113 - 2⁹ = 13329601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13330092 and 13330101.

It is not an unprimeable number, because it can be changed into a prime (13330117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2221683 + ... + 2221688.

It is an arithmetic number, because the mean of its divisors is an integer number (4443372).

Almost surely, 2^13330113 is an apocalyptic number.

It is an amenable number.

13330113 is a deficient number, since it is larger than the sum of its proper divisors (4443375).

13330113 is an equidigital number, since it uses as much as digits as its factorization.

13330113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4443374.

The product of its (nonzero) digits is 81, while the sum is 15.

The square root of 13330113 is about 3651.0427277697. The cubic root of 13330113 is about 237.1071281254.

Adding to 13330113 its reverse (31103331), we get a palindrome (44433444).

The spelling of 13330113 in words is "thirteen million, three hundred thirty thousand, one hundred thirteen".