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133100153 is a prime number
BaseRepresentation
bin1111110111011…
…11001001111001
3100021110012002022
413323233021321
5233033201103
621112444225
73204222044
oct773571171
9307405068
10133100153
116914a12a
12386a9675
13217628b4
1413969c5b
15ba42138
hex7eef279

133100153 has 2 divisors, whose sum is σ = 133100154. Its totient is φ = 133100152.

The previous prime is 133100117. The next prime is 133100167. The reversal of 133100153 is 351001331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120934009 + 12166144 = 10997^2 + 3488^2 .

It is a cyclic number.

It is not a de Polignac number, because 133100153 - 210 = 133099129 is a prime.

It is not a weakly prime, because it can be changed into another prime (133100173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550076 + 66550077.

It is an arithmetic number, because the mean of its divisors is an integer number (66550077).

Almost surely, 2133100153 is an apocalyptic number.

It is an amenable number.

133100153 is a deficient number, since it is larger than the sum of its proper divisors (1).

133100153 is an equidigital number, since it uses as much as digits as its factorization.

133100153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 133100153 is about 11536.9039607687. The cubic root of 133100153 is about 510.5749673345.

Adding to 133100153 its reverse (351001331), we get a palindrome (484101484).

The spelling of 133100153 in words is "one hundred thirty-three million, one hundred thousand, one hundred fifty-three".