Base | Representation |
---|---|
bin | 110010110000… |
… | …010100011111 |
3 | 221000222012012 |
4 | 302300110133 |
5 | 11401230434 |
6 | 1153101435 |
7 | 221043302 |
oct | 62602437 |
9 | 27028165 |
10 | 13305119 |
11 | 7568373 |
12 | 455787b |
13 | 29ab069 |
14 | 1aa4b39 |
15 | 127c3ce |
hex | cb051f |
13305119 has 2 divisors, whose sum is σ = 13305120. Its totient is φ = 13305118.
The previous prime is 13305091. The next prime is 13305133. The reversal of 13305119 is 91150331.
13305119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13305119 - 212 = 13301023 is a prime.
It is a super-2 number, since 2×133051192 = 354052383208322, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13305094 and 13305103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13305319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652559 + 6652560.
It is an arithmetic number, because the mean of its divisors is an integer number (6652560).
Almost surely, 213305119 is an apocalyptic number.
13305119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13305119 is an equidigital number, since it uses as much as digits as its factorization.
13305119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 405, while the sum is 23.
The square root of 13305119 is about 3647.6182640183. The cubic root of 13305119 is about 236.9588432274.
The spelling of 13305119 in words is "thirteen million, three hundred five thousand, one hundred nineteen".
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