Base | Representation |
---|---|
bin | 110010101110… |
… | …001100110001 |
3 | 221000112021111 |
4 | 302232030301 |
5 | 11400441213 |
6 | 1152553321 |
7 | 221006053 |
oct | 62561461 |
9 | 27015244 |
10 | 13296433 |
11 | 7561897 |
12 | 4552841 |
13 | 29a7117 |
14 | 1aa18d3 |
15 | 1279a3d |
hex | cae331 |
13296433 has 2 divisors, whose sum is σ = 13296434. Its totient is φ = 13296432.
The previous prime is 13296421. The next prime is 13296449. The reversal of 13296433 is 33469231.
13296433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8020224 + 5276209 = 2832^2 + 2297^2 .
It is an emirp because it is prime and its reverse (33469231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13296433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13296395 and 13296404.
It is not a weakly prime, because it can be changed into another prime (13296463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6648216 + 6648217.
It is an arithmetic number, because the mean of its divisors is an integer number (6648217).
Almost surely, 213296433 is an apocalyptic number.
It is an amenable number.
13296433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13296433 is an equidigital number, since it uses as much as digits as its factorization.
13296433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11664, while the sum is 31.
The square root of 13296433 is about 3646.4274296906. The cubic root of 13296433 is about 236.9072672747.
The spelling of 13296433 in words is "thirteen million, two hundred ninety-six thousand, four hundred thirty-three".
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