Base | Representation |
---|---|
bin | 100111100010001… |
… | …1100101010011001 |
3 | 10102110011112111121 |
4 | 1033010130222121 |
5 | 10204100103131 |
6 | 335344525241 |
7 | 44605424323 |
oct | 11704345231 |
9 | 3373145447 |
10 | 1326566041 |
11 | 6208a2779 |
12 | 310320821 |
13 | 181aa9c28 |
14 | c8278613 |
15 | 7b6db911 |
hex | 4f11ca99 |
1326566041 has 2 divisors, whose sum is σ = 1326566042. Its totient is φ = 1326566040.
The previous prime is 1326566011. The next prime is 1326566063. The reversal of 1326566041 is 1406656231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1296360025 + 30206016 = 36005^2 + 5496^2 .
It is a cyclic number.
It is not a de Polignac number, because 1326566041 - 29 = 1326565529 is a prime.
It is a super-2 number, since 2×13265660412 = 3519554922268827362, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1326565988 and 1326566006.
It is not a weakly prime, because it can be changed into another prime (1326566011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 663283020 + 663283021.
It is an arithmetic number, because the mean of its divisors is an integer number (663283021).
Almost surely, 21326566041 is an apocalyptic number.
It is an amenable number.
1326566041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1326566041 is an equidigital number, since it uses as much as digits as its factorization.
1326566041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 34.
The square root of 1326566041 is about 36422.0543215234. The cubic root of 1326566041 is about 1098.7771648080. Note that the first 3 decimals are identical.
The spelling of 1326566041 in words is "one billion, three hundred twenty-six million, five hundred sixty-six thousand, forty-one".
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