[go: up one dir, main page]

Search a number
-
+
1323320114 = 2661660057
BaseRepresentation
bin100111011100000…
…0100001100110010
310102020001121221002
41032320010030302
510202232220424
6335151202002
744536015064
oct11670041462
93366047832
101323320114
11619a85a96
1230b216302
1318121166c
14c7a71734
157b299cae
hex4ee04332

1323320114 has 4 divisors (see below), whose sum is σ = 1984980174. Its totient is φ = 661660056.

The previous prime is 1323320101. The next prime is 1323320147. The reversal of 1323320114 is 4110233231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 860424889 + 462895225 = 29333^2 + 21515^2 .

It is a super-2 number, since 2×13233201142 = 3502352248233945992, which contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330830027 + ... + 330830030.

Almost surely, 21323320114 is an apocalyptic number.

1323320114 is a deficient number, since it is larger than the sum of its proper divisors (661660060).

1323320114 is an equidigital number, since it uses as much as digits as its factorization.

1323320114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 661660059.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 1323320114 is about 36377.4671190835. The cubic root of 1323320114 is about 1097.8802466821.

Adding to 1323320114 its reverse (4110233231), we get a palindrome (5433553345).

The spelling of 1323320114 in words is "one billion, three hundred twenty-three million, three hundred twenty thousand, one hundred fourteen".

Divisors: 1 2 661660057 1323320114