132000403 has 4 divisors (see below), whose sum is σ = 132189408. Its totient is φ = 131811400.

The previous prime is 132000367. The next prime is 132000433. The reversal of 132000403 is 304000231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304000231 = 97 ⋅3134023.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132000403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132000433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93451 + ... + 94852.

It is an arithmetic number, because the mean of its divisors is an integer number (33047352).

Almost surely, 2^132000403 is an apocalyptic number.

132000403 is a deficient number, since it is larger than the sum of its proper divisors (189005).

132000403 is an equidigital number, since it uses as much as digits as its factorization.

132000403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 189004.

The product of its (nonzero) digits is 72, while the sum is 13.

The square root of 132000403 is about 11489.1428313865. The cubic root of 132000403 is about 509.1648551301.

Adding to 132000403 its reverse (304000231), we get a palindrome (436000634).

The spelling of 132000403 in words is "one hundred thirty-two million, four hundred three", and thus it is an aban number.