Base | Representation |
---|---|
bin | 1111101111011… |
… | …11100101001001 |
3 | 100012111000002202 |
4 | 13313233211021 |
5 | 232301201241 |
6 | 21034205545 |
7 | 3162302051 |
oct | 767574511 |
9 | 305430082 |
10 | 132053321 |
11 | 685a4684 |
12 | 382838b5 |
13 | 2148727a |
14 | 13776561 |
15 | b8d6d9b |
hex | 7def949 |
132053321 has 2 divisors, whose sum is σ = 132053322. Its totient is φ = 132053320.
The previous prime is 132053291. The next prime is 132053323. The reversal of 132053321 is 123350231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126877696 + 5175625 = 11264^2 + 2275^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132053321 is a prime.
Together with 132053323, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 132053293 and 132053302.
It is not a weakly prime, because it can be changed into another prime (132053323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026660 + 66026661.
It is an arithmetic number, because the mean of its divisors is an integer number (66026661).
Almost surely, 2132053321 is an apocalyptic number.
It is an amenable number.
132053321 is a deficient number, since it is larger than the sum of its proper divisors (1).
132053321 is an equidigital number, since it uses as much as digits as its factorization.
132053321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 20.
The square root of 132053321 is about 11491.4455574571. The cubic root of 132053321 is about 509.2328862004.
The spelling of 132053321 in words is "one hundred thirty-two million, fifty-three thousand, three hundred twenty-one".
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