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1315200151 = 6719629853
BaseRepresentation
bin100111001100100…
…0101110010010111
310101122210002102201
41032121011302113
510143142401101
6334301145331
744410005526
oct11631056227
93348702381
101315200151
1161543a381
1230855b247
1317c62a755
14c695a4bd
157a6e3e01
hex4e645c97

1315200151 has 4 divisors (see below), whose sum is σ = 1334830072. Its totient is φ = 1295570232.

The previous prime is 1315200109. The next prime is 1315200157. The reversal of 1315200151 is 1510025131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1510025131 = 4703321077.

It is a cyclic number.

It is not a de Polignac number, because 1315200151 - 219 = 1314675863 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1315200157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9814860 + ... + 9814993.

It is an arithmetic number, because the mean of its divisors is an integer number (333707518).

Almost surely, 21315200151 is an apocalyptic number.

1315200151 is a deficient number, since it is larger than the sum of its proper divisors (19629921).

1315200151 is an equidigital number, since it uses as much as digits as its factorization.

1315200151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19629920.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 1315200151 is about 36265.6883431157. The cubic root of 1315200151 is about 1095.6300873826.

Adding to 1315200151 its reverse (1510025131), we get a palindrome (2825225282).

The spelling of 1315200151 in words is "one billion, three hundred fifteen million, two hundred thousand, one hundred fifty-one".

Divisors: 1 67 19629853 1315200151