1315133503 has 4 divisors (see below), whose sum is σ = 1319107048. Its totient is φ = 1311159960.

The previous prime is 1315133483. The next prime is 1315133539. The reversal of 1315133503 is 3053315131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3053315131 = 23131 ⋅132001.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1315133503 is a prime.

It is a super-2 number, since 2×1315133503² = 3459152261426102018, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1315133003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1986276 + ... + 1986937.

It is an arithmetic number, because the mean of its divisors is an integer number (329776762).

Almost surely, 2^1315133503 is an apocalyptic number.

1315133503 is a deficient number, since it is larger than the sum of its proper divisors (3973545).

1315133503 is an equidigital number, since it uses as much as digits as its factorization.

1315133503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3973544.

The product of its (nonzero) digits is 2025, while the sum is 25.

The square root of 1315133503 is about 36264.7694463925. The cubic root of 1315133503 is about 1095.6115799872.

Adding to 1315133503 its reverse (3053315131), we get a palindrome (4368448634).

It can be divided in two parts, 1 and 315133503, that added together give a square (315133504 = 17752²).

The spelling of 1315133503 in words is "one billion, three hundred fifteen million, one hundred thirty-three thousand, five hundred three".