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1314220143 = 32671164011
BaseRepresentation
bin100111001010101…
…0110100001101111
310101120221022010010
41032111112201233
510142420021033
6334224144303
744365454415
oct11625264157
93346838103
101314220143
11614930055
12308168093
1317c376672
14c67832b5
157a59d863
hex4e55686f

1314220143 has 8 divisors (see below), whose sum is σ = 1752960256. Its totient is φ = 875813400.

The previous prime is 1314220111. The next prime is 1314220163. The reversal of 1314220143 is 3410224131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1314220143 - 25 = 1314220111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314220163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73993 + ... + 90018.

It is an arithmetic number, because the mean of its divisors is an integer number (219120032).

Almost surely, 21314220143 is an apocalyptic number.

1314220143 is a deficient number, since it is larger than the sum of its proper divisors (438740113).

1314220143 is a wasteful number, since it uses less digits than its factorization.

1314220143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 166685.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 1314220143 is about 36252.1743209976. The cubic root of 1314220143 is about 1095.3578872280.

Adding to 1314220143 its reverse (3410224131), we get a palindrome (4724444274).

The spelling of 1314220143 in words is "one billion, three hundred fourteen million, two hundred twenty thousand, one hundred forty-three".

Divisors: 1 3 2671 8013 164011 492033 438073381 1314220143