[go: up one dir, main page]

Search a number
-
+
131401441 is a prime number
BaseRepresentation
bin1111101010100…
…00011011100001
3100011020212220001
413311100123201
5232114321231
621012220001
73153615403
oct765203341
9304225801
10131401441
1168199936
123800a601
13212b9642
1413646b73
15b808b61
hex7d506e1

131401441 has 2 divisors, whose sum is σ = 131401442. Its totient is φ = 131401440.

The previous prime is 131401429. The next prime is 131401451. The reversal of 131401441 is 144104131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73702225 + 57699216 = 8585^2 + 7596^2 .

It is a cyclic number.

It is not a de Polignac number, because 131401441 - 25 = 131401409 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131401451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65700720 + 65700721.

It is an arithmetic number, because the mean of its divisors is an integer number (65700721).

Almost surely, 2131401441 is an apocalyptic number.

It is an amenable number.

131401441 is a deficient number, since it is larger than the sum of its proper divisors (1).

131401441 is an equidigital number, since it uses as much as digits as its factorization.

131401441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 131401441 is about 11463.0467590427. The cubic root of 131401441 is about 508.3935624297.

Adding to 131401441 its reverse (144104131), we get a palindrome (275505572).

The spelling of 131401441 in words is "one hundred thirty-one million, four hundred one thousand, four hundred forty-one".