1314434031 has 4 divisors (see below), whose sum is σ = 1752578712. Its totient is φ = 876289352.

The previous prime is 1314433997. The next prime is 1314434059. The reversal of 1314434031 is 1304344131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1304344131 = 3 ⋅434781377.

It is a cyclic number.

It is not a de Polignac number, because 1314434031 - 2¹⁰ = 1314433007 is a prime.

It is a super-2 number, since 2×1314434031² = 3455473643701817922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314433992 and 1314434010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314434071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219072336 + ... + 219072341.

It is an arithmetic number, because the mean of its divisors is an integer number (438144678).

Almost surely, 2^1314434031 is an apocalyptic number.

1314434031 is a deficient number, since it is larger than the sum of its proper divisors (438144681).

1314434031 is an equidigital number, since it uses as much as digits as its factorization.

1314434031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 438144680.

The product of its (nonzero) digits is 1728, while the sum is 24.

The square root of 1314434031 is about 36255.1242033454. The cubic root of 1314434031 is about 1095.4173068010.

Adding to 1314434031 its reverse (1304344131), we get a palindrome (2618778162).

The spelling of 1314434031 in words is "one billion, three hundred fourteen million, four hundred thirty-four thousand, thirty-one".