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1313522437 is a prime number
BaseRepresentation
bin100111001001010…
…1100001100000101
310101112121212001011
41032102230030011
510142230204222
6334201202221
744356520323
oct11622541405
93345555034
101313522437
116144a3937
12307a90371
1317c190c16
14c6640d13
157a4b1c77
hex4e4ac305

1313522437 has 2 divisors, whose sum is σ = 1313522438. Its totient is φ = 1313522436.

The previous prime is 1313522423. The next prime is 1313522461. The reversal of 1313522437 is 7342253131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 760049761 + 553472676 = 27569^2 + 23526^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313522437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313522399 and 1313522408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313522467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656761218 + 656761219.

It is an arithmetic number, because the mean of its divisors is an integer number (656761219).

Almost surely, 21313522437 is an apocalyptic number.

It is an amenable number.

1313522437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313522437 is an equidigital number, since it uses as much as digits as its factorization.

1313522437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15120, while the sum is 31.

The square root of 1313522437 is about 36242.5500896391. The cubic root of 1313522437 is about 1095.1640148249.

Adding to 1313522437 its reverse (7342253131), we get a palindrome (8655775568).

The spelling of 1313522437 in words is "one billion, three hundred thirteen million, five hundred twenty-two thousand, four hundred thirty-seven".