1311000511 has 2 divisors, whose sum is σ = 1311000512. Its totient is φ = 1311000510.

The previous prime is 1311000491. The next prime is 1311000533. The reversal of 1311000511 is 1150001131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1311000511 - 2⁵ = 1311000479 is a prime.

It is a super-2 number, since 2×1311000511² = 3437444679684522242, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311000491 and 1311000500.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311070511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655500255 + 655500256.

It is an arithmetic number, because the mean of its divisors is an integer number (655500256).

Almost surely, 2^1311000511 is an apocalyptic number.

1311000511 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311000511 is an equidigital number, since it uses as much as digits as its factorization.

1311000511 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 13.

The square root of 1311000511 is about 36207.7410369661. The cubic root of 1311000511 is about 1094.4626711154.

Adding to 1311000511 its reverse (1150001131), we get a palindrome (2461001642).

The spelling of 1311000511 in words is "one billion, three hundred eleven million, five hundred eleven", and thus it is an aban number.