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1310354113 is a prime number
BaseRepresentation
bin100111000011010…
…0110101011000001
310101022122212220211
41032012212223001
510140422312423
6334005234121
744320553245
oct11606465301
93338585824
101310354113
1161272a492
12306a02941
1317b621a83
14c6058425
157a08810d
hex4e1a6ac1

1310354113 has 2 divisors, whose sum is σ = 1310354114. Its totient is φ = 1310354112.

The previous prime is 1310354077. The next prime is 1310354141. The reversal of 1310354113 is 3114530131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 901020289 + 409333824 = 30017^2 + 20232^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310354113 - 217 = 1310223041 is a prime.

It is not a weakly prime, because it can be changed into another prime (1310354153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655177056 + 655177057.

It is an arithmetic number, because the mean of its divisors is an integer number (655177057).

Almost surely, 21310354113 is an apocalyptic number.

It is an amenable number.

1310354113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310354113 is an equidigital number, since it uses as much as digits as its factorization.

1310354113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 1310354113 is about 36198.8136960315. The cubic root of 1310354113 is about 1094.2827640444.

Adding to 1310354113 its reverse (3114530131), we get a palindrome (4424884244).

The spelling of 1310354113 in words is "one billion, three hundred ten million, three hundred fifty-four thousand, one hundred thirteen".