Base | Representation |
---|---|
bin | 100111000011001… |
… | …1111100110000011 |
3 | 10101022121102011010 |
4 | 1032012133212003 |
5 | 10140420400443 |
6 | 334004452003 |
7 | 44320402602 |
oct | 11606374603 |
9 | 3338542133 |
10 | 1310325123 |
11 | 61270a728 |
12 | 3069aa003 |
13 | 17b611813 |
14 | c604ba39 |
15 | 7a07e733 |
hex | 4e19f983 |
1310325123 has 4 divisors (see below), whose sum is σ = 1747100168. Its totient is φ = 873550080.
The previous prime is 1310325119. The next prime is 1310325127. The reversal of 1310325123 is 3215230131.
1310325123 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (1310325119) and next prime (1310325127).
It is not a de Polignac number, because 1310325123 - 22 = 1310325119 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1310325123.
It is not an unprimeable number, because it can be changed into a prime (1310325127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218387518 + ... + 218387523.
It is an arithmetic number, because the mean of its divisors is an integer number (436775042).
Almost surely, 21310325123 is an apocalyptic number.
1310325123 is a deficient number, since it is larger than the sum of its proper divisors (436775045).
1310325123 is an equidigital number, since it uses as much as digits as its factorization.
1310325123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 436775044.
The product of its (nonzero) digits is 540, while the sum is 21.
The square root of 1310325123 is about 36198.4132663298. The cubic root of 1310325123 is about 1094.2746940906.
Adding to 1310325123 its reverse (3215230131), we get a palindrome (4525555254).
It can be divided in two parts, 13103 and 25123, that added together give a triangular number (38226 = T276).
The spelling of 1310325123 in words is "one billion, three hundred ten million, three hundred twenty-five thousand, one hundred twenty-three".
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