1310232113 has 4 divisors (see below), whose sum is σ = 1338109440. Its totient is φ = 1282354788.

The previous prime is 1310232103. The next prime is 1310232137. The reversal of 1310232113 is 3112320131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3112320131 = 673 ⋅4624547.

It is a cyclic number.

It is not a de Polignac number, because 1310232113 - 2¹⁴ = 1310215729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310232091 and 1310232100.

It is not an unprimeable number, because it can be changed into a prime (1310232103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13938593 + ... + 13938686.

It is an arithmetic number, because the mean of its divisors is an integer number (334527360).

Almost surely, 2^1310232113 is an apocalyptic number.

It is an amenable number.

1310232113 is a deficient number, since it is larger than the sum of its proper divisors (27877327).

1310232113 is an equidigital number, since it uses as much as digits as its factorization.

1310232113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27877326.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1310232113 is about 36197.1285187099. The cubic root of 1310232113 is about 1094.2488020694.

Adding to 1310232113 its reverse (3112320131), we get a palindrome (4422552244).

The spelling of 1310232113 in words is "one billion, three hundred ten million, two hundred thirty-two thousand, one hundred thirteen".