1310140111 has 4 divisors (see below), whose sum is σ = 1497302992. Its totient is φ = 1122977232.

The previous prime is 1310140109. The next prime is 1310140129. The reversal of 1310140111 is 1110410131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1110410131 = 17 ⋅65318243.

It is a cyclic number.

It is not a de Polignac number, because 1310140111 - 2¹ = 1310140109 is a prime.

It is a super-2 number, since 2×1310140111² = 3432934220902184642, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310140091 and 1310140100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310140151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93581430 + ... + 93581443.

It is an arithmetic number, because the mean of its divisors is an integer number (374325748).

Almost surely, 2^1310140111 is an apocalyptic number.

1310140111 is a deficient number, since it is larger than the sum of its proper divisors (187162881).

1310140111 is an equidigital number, since it uses as much as digits as its factorization.

1310140111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 187162880.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 1310140111 is about 36195.8576497367. The cubic root of 1310140111 is about 1094.2231894486.

Adding to 1310140111 its reverse (1110410131), we get a palindrome (2420550242).

The spelling of 1310140111 in words is "one billion, three hundred ten million, one hundred forty thousand, one hundred eleven".