Base | Representation |
---|---|
bin | 100111000010110… |
… | …1110100001011001 |
3 | 10101022020012102121 |
4 | 1032011232201121 |
5 | 10140342432441 |
6 | 334000301241 |
7 | 44315604565 |
oct | 11605564131 |
9 | 3338205377 |
10 | 1310124121 |
11 | 612592709 |
12 | 306911821 |
13 | 17b571197 |
14 | c5dd86a5 |
15 | 7a03edd1 |
hex | 4e16e859 |
1310124121 has 2 divisors, whose sum is σ = 1310124122. Its totient is φ = 1310124120.
The previous prime is 1310124113. The next prime is 1310124131. The reversal of 1310124121 is 1214210131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1007364121 + 302760000 = 31739^2 + 17400^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310124121 - 23 = 1310124113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310124095 and 1310124104.
It is not a weakly prime, because it can be changed into another prime (1310124131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655062060 + 655062061.
It is an arithmetic number, because the mean of its divisors is an integer number (655062061).
Almost surely, 21310124121 is an apocalyptic number.
It is an amenable number.
1310124121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310124121 is an equidigital number, since it uses as much as digits as its factorization.
1310124121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
The square root of 1310124121 is about 36195.6367674337. The cubic root of 1310124121 is about 1094.2187378383.
Adding to 1310124121 its reverse (1214210131), we get a palindrome (2524334252).
The spelling of 1310124121 in words is "one billion, three hundred ten million, one hundred twenty-four thousand, one hundred twenty-one".
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