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1310005441 is a prime number
BaseRepresentation
bin100111000010101…
…0001100011000001
310101022000011122001
41032011101203001
510140330133231
6333553544001
744314601563
oct11605214301
93338004561
101310005441
11612511528
12306875001
1317b52c164
14c5da7333
157a019b61
hex4e1518c1

1310005441 has 2 divisors, whose sum is σ = 1310005442. Its totient is φ = 1310005440.

The previous prime is 1310005427. The next prime is 1310005447. The reversal of 1310005441 is 1445000131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1203812416 + 106193025 = 34696^2 + 10305^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310005441 - 221 = 1307908289 is a prime.

It is a super-2 number, since 2×13100054412 = 3432228510899208962, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310005447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655002720 + 655002721.

It is an arithmetic number, because the mean of its divisors is an integer number (655002721).

Almost surely, 21310005441 is an apocalyptic number.

It is an amenable number.

1310005441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310005441 is an equidigital number, since it uses as much as digits as its factorization.

1310005441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 1310005441 is about 36193.9973061832. The cubic root of 1310005441 is about 1094.1856962358.

Adding to 1310005441 its reverse (1445000131), we get a palindrome (2755005572).

The spelling of 1310005441 in words is "one billion, three hundred ten million, five thousand, four hundred forty-one".