1310000141 has 4 divisors (see below), whose sum is σ = 1314870300. Its totient is φ = 1305129984.

The previous prime is 1310000101. The next prime is 1310000149. The reversal of 1310000141 is 1410000131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1410000131 = 389 ⋅3624679.

It can be written as a sum of positive squares in 2 ways, for example, as 673194916 + 636805225 = 25946^2 + 25235^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310000141 - 2³⁰ = 236258317 is a prime.

It is a super-2 number, since 2×1310000141² = 3432200738840039762, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310000149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2434676 + ... + 2435213.

It is an arithmetic number, because the mean of its divisors is an integer number (328717575).

Almost surely, 2^1310000141 is an apocalyptic number.

It is an amenable number.

1310000141 is a deficient number, since it is larger than the sum of its proper divisors (4870159).

1310000141 is an equidigital number, since it uses as much as digits as its factorization.

1310000141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4870158.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1310000141 is about 36193.9240895485. The cubic root of 1310000141 is about 1094.1842206205.

Adding to 1310000141 its reverse (1410000131), we get a palindrome (2720000272).

The spelling of 1310000141 in words is "one billion, three hundred ten million, one hundred forty-one", and thus it is an aban number.