130410041 has 2 divisors, whose sum is σ = 130410042. Its totient is φ = 130410040.

The previous prime is 130410037. The next prime is 130410061. The reversal of 130410041 is 140014031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74459641 + 55950400 = 8629^2 + 7480^2 .

It is a cyclic number.

It is not a de Polignac number, because 130410041 - 2² = 130410037 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130409998 and 130410025.

It is not a weakly prime, because it can be changed into another prime (130410061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205020 + 65205021.

It is an arithmetic number, because the mean of its divisors is an integer number (65205021).

Almost surely, 2^130410041 is an apocalyptic number.

It is an amenable number.

130410041 is a deficient number, since it is larger than the sum of its proper divisors (1).

130410041 is an equidigital number, since it uses as much as digits as its factorization.

130410041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 130410041 is about 11419.7215815448. The cubic root of 130410041 is about 507.1117543125. Note that the first 3 decimals are identical.

Adding to 130410041 its reverse (140014031), we get a palindrome (270424072).

The spelling of 130410041 in words is "one hundred thirty million, four hundred ten thousand, forty-one".