Base | Representation |
---|---|
bin | 100110110010000… |
… | …1010011011100011 |
3 | 10100200200012001012 |
4 | 1031210022123203 |
5 | 10131114404124 |
6 | 333043531135 |
7 | 44151041003 |
oct | 11544123343 |
9 | 3320605035 |
10 | 1301325539 |
11 | 608623158 |
12 | 303989aab |
13 | 1797b0417 |
14 | c4b88003 |
15 | 793a2e0e |
hex | 4d90a6e3 |
1301325539 has 2 divisors, whose sum is σ = 1301325540. Its totient is φ = 1301325538.
The previous prime is 1301325481. The next prime is 1301325541. The reversal of 1301325539 is 9355231031.
It is a strong prime.
It is an emirp because it is prime and its reverse (9355231031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1301325539 - 28 = 1301325283 is a prime.
Together with 1301325541, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1301325569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650662769 + 650662770.
It is an arithmetic number, because the mean of its divisors is an integer number (650662770).
Almost surely, 21301325539 is an apocalyptic number.
1301325539 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301325539 is an equidigital number, since it uses as much as digits as its factorization.
1301325539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12150, while the sum is 32.
The square root of 1301325539 is about 36073.8899898528. The cubic root of 1301325539 is about 1091.7637016272.
The spelling of 1301325539 in words is "one billion, three hundred one million, three hundred twenty-five thousand, five hundred thirty-nine".
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