Base | Representation |
---|---|
bin | 100110110001011… |
… | …1101111010010101 |
3 | 10100200002021002222 |
4 | 1031202331322111 |
5 | 10131024341432 |
6 | 333033112125 |
7 | 44145264146 |
oct | 11542757225 |
9 | 3320067088 |
10 | 1301012117 |
11 | 608429729 |
12 | 303858645 |
13 | 179700872 |
14 | c4b05acd |
15 | 79340112 |
hex | 4d8bde95 |
1301012117 has 2 divisors, whose sum is σ = 1301012118. Its totient is φ = 1301012116.
The previous prime is 1301012101. The next prime is 1301012161. The reversal of 1301012117 is 7112101031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 804346321 + 496665796 = 28361^2 + 22286^2 .
It is a cyclic number.
It is not a de Polignac number, because 1301012117 - 24 = 1301012101 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1301012095 and 1301012104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1301012177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650506058 + 650506059.
It is an arithmetic number, because the mean of its divisors is an integer number (650506059).
Almost surely, 21301012117 is an apocalyptic number.
It is an amenable number.
1301012117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301012117 is an equidigital number, since it uses as much as digits as its factorization.
1301012117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 17.
The square root of 1301012117 is about 36069.5455613181. The cubic root of 1301012117 is about 1091.6760447912.
Adding to 1301012117 its reverse (7112101031), we get a palindrome (8413113148).
The spelling of 1301012117 in words is "one billion, three hundred one million, twelve thousand, one hundred seventeen".
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