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130000403 = 1322744053
BaseRepresentation
bin1111011111110…
…10011000010011
3100001121201000202
413233322120103
5231240003103
620522205415
73135661631
oct757723023
9301551022
10130000403
1167422255
123765386b
1320c18a20
14133a0351
15b62d988
hex7bfa613

130000403 has 8 divisors (see below), whose sum is σ = 140620368. Its totient is φ = 119469024.

The previous prime is 130000363. The next prime is 130000421. The reversal of 130000403 is 304000031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130000403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130000483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19076 + ... + 24977.

It is an arithmetic number, because the mean of its divisors is an integer number (17577546).

Almost surely, 2130000403 is an apocalyptic number.

130000403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

130000403 is a deficient number, since it is larger than the sum of its proper divisors (10619965).

130000403 is a wasteful number, since it uses less digits than its factorization.

130000403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44293.

The product of its (nonzero) digits is 36, while the sum is 11.

The square root of 130000403 is about 11401.7719236968. The cubic root of 130000403 is about 506.5802253752.

Adding to 130000403 its reverse (304000031), we get a palindrome (434000434).

The spelling of 130000403 in words is "one hundred thirty million, four hundred three", and thus it is an aban number.

Divisors: 1 13 227 2951 44053 572689 10000031 130000403