Base | Representation |
---|---|
bin | 100110110001010… |
… | …1001011110111001 |
3 | 10100122221000022212 |
4 | 1031202221132321 |
5 | 10131014202231 |
6 | 333031224505 |
7 | 44144465201 |
oct | 11542513671 |
9 | 3318830285 |
10 | 1300928441 |
11 | 60838187a |
12 | 303818135 |
13 | 1796a1757 |
14 | c4ac3401 |
15 | 7932542b |
hex | 4d8a97b9 |
1300928441 has 2 divisors, whose sum is σ = 1300928442. Its totient is φ = 1300928440.
The previous prime is 1300928413. The next prime is 1300928443. The reversal of 1300928441 is 1448290031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 956046400 + 344882041 = 30920^2 + 18571^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1300928441 is a prime.
Together with 1300928443, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1300928398 and 1300928407.
It is not a weakly prime, because it can be changed into another prime (1300928443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650464220 + 650464221.
It is an arithmetic number, because the mean of its divisors is an integer number (650464221).
Almost surely, 21300928441 is an apocalyptic number.
It is an amenable number.
1300928441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300928441 is an equidigital number, since it uses as much as digits as its factorization.
1300928441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 32.
The square root of 1300928441 is about 36068.3856167697. The cubic root of 1300928441 is about 1091.6526401813.
The spelling of 1300928441 in words is "one billion, three hundred million, nine hundred twenty-eight thousand, four hundred forty-one".
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