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1245400147 is a prime number
BaseRepresentation
bin100101000111011…
…0100110001010011
310012210102212211101
41022032310301103
510022310301042
6323325125231
742601504135
oct11216646123
93183385741
101245400147
11589aa5622
122a90b9817
1316b02bc84
14bb58b055
15745076b7
hex4a3b4c53

1245400147 has 2 divisors, whose sum is σ = 1245400148. Its totient is φ = 1245400146.

The previous prime is 1245400109. The next prime is 1245400151. The reversal of 1245400147 is 7410045421.

It is a strong prime.

It is an emirp because it is prime and its reverse (7410045421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1245400147 - 215 = 1245367379 is a prime.

It is a super-2 number, since 2×12454001472 = 3102043052295243218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1245400547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622700073 + 622700074.

It is an arithmetic number, because the mean of its divisors is an integer number (622700074).

Almost surely, 21245400147 is an apocalyptic number.

1245400147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1245400147 is an equidigital number, since it uses as much as digits as its factorization.

1245400147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4480, while the sum is 28.

The square root of 1245400147 is about 35290.2273582928. The cubic root of 1245400147 is about 1075.8943765140.

Adding to 1245400147 its reverse (7410045421), we get a palindrome (8655445568).

The spelling of 1245400147 in words is "one billion, two hundred forty-five million, four hundred thousand, one hundred forty-seven".