Base | Representation |
---|---|
bin | 101110100101… |
… | …011110010001 |
3 | 211222102212111 |
4 | 232211132101 |
5 | 11111241423 |
6 | 1113425321 |
7 | 205541554 |
oct | 56453621 |
9 | 24872774 |
10 | 12212113 |
11 | 6991161 |
12 | 410b241 |
13 | 26b7704 |
14 | 189c69b |
15 | 111360d |
hex | ba5791 |
12212113 has 2 divisors, whose sum is σ = 12212114. Its totient is φ = 12212112.
The previous prime is 12212111. The next prime is 12212119. The reversal of 12212113 is 31121221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7935489 + 4276624 = 2817^2 + 2068^2 .
It is a cyclic number.
It is not a de Polignac number, because 12212113 - 21 = 12212111 is a prime.
Together with 12212111, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 12212093 and 12212102.
It is not a weakly prime, because it can be changed into another prime (12212111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106056 + 6106057.
It is an arithmetic number, because the mean of its divisors is an integer number (6106057).
Almost surely, 212212113 is an apocalyptic number.
It is an amenable number.
12212113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212113 is an equidigital number, since it uses as much as digits as its factorization.
12212113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 24, while the sum is 13.
The square root of 12212113 is about 3494.5833800326. The cubic root of 12212113 is about 230.2839152972.
Adding to 12212113 its reverse (31121221), we get a palindrome (43333334).
The spelling of 12212113 in words is "twelve million, two hundred twelve thousand, one hundred thirteen".
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