Base | Representation |
---|---|
bin | 100100011000000… |
… | …0011000101101001 |
3 | 10011001200121211221 |
4 | 1020300003011221 |
5 | 4444430230423 |
6 | 321040422041 |
7 | 42150355501 |
oct | 11060030551 |
9 | 3131617757 |
10 | 1220555113 |
11 | 576a76138 |
12 | 2a0917921 |
13 | 165b4047b |
14 | b8160a01 |
15 | 7224ae5d |
hex | 48c03169 |
1220555113 has 2 divisors, whose sum is σ = 1220555114. Its totient is φ = 1220555112.
The previous prime is 1220555111. The next prime is 1220555207. The reversal of 1220555113 is 3115550221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 702674064 + 517881049 = 26508^2 + 22757^2 .
It is a cyclic number.
It is not a de Polignac number, because 1220555113 - 21 = 1220555111 is a prime.
Together with 1220555111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1220555111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610277556 + 610277557.
It is an arithmetic number, because the mean of its divisors is an integer number (610277557).
Almost surely, 21220555113 is an apocalyptic number.
It is an amenable number.
1220555113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220555113 is an equidigital number, since it uses as much as digits as its factorization.
1220555113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1500, while the sum is 25.
The square root of 1220555113 is about 34936.4439089041. The cubic root of 1220555113 is about 1068.6917697125.
The spelling of 1220555113 in words is "one billion, two hundred twenty million, five hundred fifty-five thousand, one hundred thirteen".
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