Base | Representation |
---|---|
bin | 100100001001110… |
… | …0111010101111001 |
3 | 10010112122221022201 |
4 | 1020103213111321 |
5 | 4441023221213 |
6 | 320212550201 |
7 | 42030122605 |
oct | 11023472571 |
9 | 3115587281 |
10 | 1213101433 |
11 | 572845075 |
12 | 29a322361 |
13 | 1644308cb |
14 | b7180505 |
15 | 717776dd |
hex | 484e7579 |
1213101433 has 2 divisors, whose sum is σ = 1213101434. Its totient is φ = 1213101432.
The previous prime is 1213101427. The next prime is 1213101451. The reversal of 1213101433 is 3341013121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 950920569 + 262180864 = 30837^2 + 16192^2 .
It is a cyclic number.
It is not a de Polignac number, because 1213101433 - 221 = 1211004281 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1213101433.
It is not a weakly prime, because it can be changed into another prime (1213101133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606550716 + 606550717.
It is an arithmetic number, because the mean of its divisors is an integer number (606550717).
Almost surely, 21213101433 is an apocalyptic number.
It is an amenable number.
1213101433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213101433 is an equidigital number, since it uses as much as digits as its factorization.
1213101433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
The square root of 1213101433 is about 34829.6056968781. The cubic root of 1213101433 is about 1066.5118991055.
Adding to 1213101433 its reverse (3341013121), we get a palindrome (4554114554).
The spelling of 1213101433 in words is "one billion, two hundred thirteen million, one hundred one thousand, four hundred thirty-three".
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