1211045533 has 2 divisors, whose sum is σ = 1211045534. Its totient is φ = 1211045532.

The previous prime is 1211045531. The next prime is 1211045567. The reversal of 1211045533 is 3355401121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1031565924 + 179479609 = 32118^2 + 13397^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211045533 - 2¹ = 1211045531 is a prime.

Together with 1211045531, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1211045498 and 1211045507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211045531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605522766 + 605522767.

It is an arithmetic number, because the mean of its divisors is an integer number (605522767).

Almost surely, 2^1211045533 is an apocalyptic number.

It is an amenable number.

1211045533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211045533 is an equidigital number, since it uses as much as digits as its factorization.

1211045533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 1211045533 is about 34800.0794970356. The cubic root of 1211045533 is about 1065.9090691527.

Adding to 1211045533 its reverse (3355401121), we get a palindrome (4566446654).

The spelling of 1211045533 in words is "one billion, two hundred eleven million, forty-five thousand, five hundred thirty-three".