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12114303 = 336711003
BaseRepresentation
bin101110001101…
…100101111111
3211210110200220
4232031211333
511100124203
61111352423
7204653445
oct56154577
924713626
1012114303
116924723
124082713
132682036
141874b95
1510e4653
hexb8d97f

12114303 has 8 divisors (see below), whose sum is σ = 16197888. Its totient is φ = 8053464.

The previous prime is 12114299. The next prime is 12114313. The reversal of 12114303 is 30341121.

12114303 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12114303 - 22 = 12114299 is a prime.

It is a super-3 number, since 3×121143033 (a number of 22 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4401 + ... + 6602.

It is an arithmetic number, because the mean of its divisors is an integer number (2024736).

Almost surely, 212114303 is an apocalyptic number.

12114303 is a deficient number, since it is larger than the sum of its proper divisors (4083585).

12114303 is a wasteful number, since it uses less digits than its factorization.

12114303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11373.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 12114303 is about 3480.5607306869. The cubic root of 12114303 is about 229.6674652616.

Adding to 12114303 its reverse (30341121), we get a palindrome (42455424).

The spelling of 12114303 in words is "twelve million, one hundred fourteen thousand, three hundred three".

Divisors: 1 3 367 1101 11003 33009 4038101 12114303