12024113 has 2 divisors, whose sum is σ = 12024114. Its totient is φ = 12024112.

The previous prime is 12024109. The next prime is 12024119. The reversal of 12024113 is 31142021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8898289 + 3125824 = 2983^2 + 1768^2 .

It is an emirp because it is prime and its reverse (31142021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12024113 - 2² = 12024109 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12024119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6012056 + 6012057.

It is an arithmetic number, because the mean of its divisors is an integer number (6012057).

Almost surely, 2^12024113 is an apocalyptic number.

It is an amenable number.

12024113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12024113 is an equidigital number, since it uses as much as digits as its factorization.

12024113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 12024113 is about 3467.5802802531. The cubic root of 12024113 is about 229.0960931042.

Adding to 12024113 its reverse (31142021), we get a palindrome (43166134).

The spelling of 12024113 in words is "twelve million, twenty-four thousand, one hundred thirteen".