Base | Representation |
---|---|
bin | 100011110011010… |
… | …0110101001110011 |
3 | 10002201110110201112 |
4 | 1013212212221303 |
5 | 4430013132011 |
6 | 315112023535 |
7 | 41524620401 |
oct | 10746465163 |
9 | 3081413645 |
10 | 1201302131 |
11 | 567116087 |
12 | 296391bab |
13 | 161b5c083 |
14 | b578c471 |
15 | 706e658b |
hex | 479a6a73 |
1201302131 has 2 divisors, whose sum is σ = 1201302132. Its totient is φ = 1201302130.
The previous prime is 1201302103. The next prime is 1201302133. The reversal of 1201302131 is 1312031021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201302131 is a prime.
It is a super-2 number, since 2×12013021312 = 2886253619890282322, which contains 22 as substring.
Together with 1201302133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1201302133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600651065 + 600651066.
It is an arithmetic number, because the mean of its divisors is an integer number (600651066).
Almost surely, 21201302131 is an apocalyptic number.
1201302131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201302131 is an equidigital number, since it uses as much as digits as its factorization.
1201302131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 14.
The square root of 1201302131 is about 34659.8056976666. The cubic root of 1201302131 is about 1063.0427970912.
Adding to 1201302131 its reverse (1312031021), we get a palindrome (2513333152).
The spelling of 1201302131 in words is "one billion, two hundred one million, three hundred two thousand, one hundred thirty-one".
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