12018401 has 2 divisors, whose sum is σ = 12018402. Its totient is φ = 12018400.

The previous prime is 12018353. The next prime is 12018437. The reversal of 12018401 is 10481021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6838225 + 5180176 = 2615^2 + 2276^2 .

It is an emirp because it is prime and its reverse (10481021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12018401 - 2¹⁸ = 11756257 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12018401.

It is not a weakly prime, because it can be changed into another prime (12018481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6009200 + 6009201.

It is an arithmetic number, because the mean of its divisors is an integer number (6009201).

Almost surely, 2^12018401 is an apocalyptic number.

It is an amenable number.

12018401 is a deficient number, since it is larger than the sum of its proper divisors (1).

12018401 is an equidigital number, since it uses as much as digits as its factorization.

12018401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

The square root of 12018401 is about 3466.7565533219. The cubic root of 12018401 is about 229.0598103405.

Adding to 12018401 its reverse (10481021), we get a palindrome (22499422).

The spelling of 12018401 in words is "twelve million, eighteen thousand, four hundred one".