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12016131 = 34005377
BaseRepresentation
bin101101110101…
…101000000011
3211121111000220
4231311220003
511034004011
61105314123
7204064311
oct55655003
924544026
1012016131
116867996
124035943
13264944a
14184b0b1
1510c5506
hexb75a03

12016131 has 4 divisors (see below), whose sum is σ = 16021512. Its totient is φ = 8010752.

The previous prime is 12016129. The next prime is 12016139. The reversal of 12016131 is 13161021.

12016131 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12016131 - 21 = 12016129 is a prime.

It is a super-2 number, since 2×120161312 = 288774808418322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12016131.

It is not an unprimeable number, because it can be changed into a prime (12016139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002686 + ... + 2002691.

It is an arithmetic number, because the mean of its divisors is an integer number (4005378).

Almost surely, 212016131 is an apocalyptic number.

12016131 is a deficient number, since it is larger than the sum of its proper divisors (4005381).

12016131 is an equidigital number, since it uses as much as digits as its factorization.

12016131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4005380.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 12016131 is about 3466.4291425039. The cubic root of 12016131 is about 229.0453880528.

Adding to 12016131 its reverse (13161021), we get a palindrome (25177152).

The spelling of 12016131 in words is "twelve million, sixteen thousand, one hundred thirty-one".

Divisors: 1 3 4005377 12016131