1200420043 has 4 divisors (see below), whose sum is σ = 1200573088. Its totient is φ = 1200267000.

The previous prime is 1200420029. The next prime is 1200420059. The reversal of 1200420043 is 3400240021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3400240021 = 337 ⋅10089733.

It is a cyclic number.

It is not a de Polignac number, because 1200420043 - 2¹³ = 1200411851 is a prime.

It is a super-2 number, since 2×1200420043² = 2882016559272243698, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200419999 and 1200420026.

It is not an unprimeable number, because it can be changed into a prime (1200420083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64083 + ... + 80668.

It is an arithmetic number, because the mean of its divisors is an integer number (300143272).

Almost surely, 2^1200420043 is an apocalyptic number.

1200420043 is a deficient number, since it is larger than the sum of its proper divisors (153045).

1200420043 is an equidigital number, since it uses as much as digits as its factorization.

1200420043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153044.

The product of its (nonzero) digits is 192, while the sum is 16.

The square root of 1200420043 is about 34647.0784193992. The cubic root of 1200420043 is about 1062.7825442444.

Adding to 1200420043 its reverse (3400240021), we get a palindrome (4600660064).

The spelling of 1200420043 in words is "one billion, two hundred million, four hundred twenty thousand, forty-three".