Base | Representation |
---|---|
bin | 100011110001100… |
… | …1101001010110000 |
3 | 10002122210012202020 |
4 | 1013203031022300 |
5 | 4424301130222 |
6 | 315040551440 |
7 | 41514220302 |
oct | 10743151260 |
9 | 3078705666 |
10 | 1200411312 |
11 | 566667871 |
12 | 296022580 |
13 | 161909769 |
14 | b55d9972 |
15 | 705bc65c |
hex | 478cd2b0 |
1200411312 has 20 divisors (see below), whose sum is σ = 3101062680. Its totient is φ = 400137088.
The previous prime is 1200411301. The next prime is 1200411341. The reversal of 1200411312 is 2131140021.
It is a super-2 number, since 2×12004113122 = 2881974635955122688, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1200411291 and 1200411300.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12504237 + ... + 12504332.
It is an arithmetic number, because the mean of its divisors is an integer number (155053134).
Almost surely, 21200411312 is an apocalyptic number.
1200411312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1200411312 is an abundant number, since it is smaller than the sum of its proper divisors (1900651368).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1200411312 is a wasteful number, since it uses less digits than its factorization.
1200411312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25008580 (or 25008574 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
The square root of 1200411312 is about 34646.9524200903. The cubic root of 1200411312 is about 1062.7799675972.
Adding to 1200411312 its reverse (2131140021), we get a palindrome (3331551333).
The spelling of 1200411312 in words is "one billion, two hundred million, four hundred eleven thousand, three hundred twelve".
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