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119534431 is a prime number
BaseRepresentation
bin1110001111111…
…11001101011111
322022220222102011
413013333031133
5221100100211
615510012051
72651011612
oct707771537
9268828364
10119534431
1161523a95
1234047027
131b9c3043
1411c38179
15a762921
hex71ff35f

119534431 has 2 divisors, whose sum is σ = 119534432. Its totient is φ = 119534430.

The previous prime is 119534423. The next prime is 119534447. The reversal of 119534431 is 134435911.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 119534431 - 23 = 119534423 is a prime.

It is a super-2 number, since 2×1195344312 = 28576960388987522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 119534393 and 119534402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119544431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59767215 + 59767216.

It is an arithmetic number, because the mean of its divisors is an integer number (59767216).

Almost surely, 2119534431 is an apocalyptic number.

119534431 is a deficient number, since it is larger than the sum of its proper divisors (1).

119534431 is an equidigital number, since it uses as much as digits as its factorization.

119534431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6480, while the sum is 31.

The square root of 119534431 is about 10933.1802784002. The cubic root of 119534431 is about 492.6037037583.

It can be divided in two parts, 11953 and 4431, that added together give a 14-th power (16384 = 214).

The spelling of 119534431 in words is "one hundred nineteen million, five hundred thirty-four thousand, four hundred thirty-one".