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115520141 = 1110501831
BaseRepresentation
bin1101110001010…
…11001010001101
322001101000211202
412320223022031
5214033121031
615243555245
72601622262
oct670531215
9261330752
10115520141
115a231aa0
123282bb25
131ac18b19
14114b1269
15a21d2cb
hex6e2b28d

115520141 has 4 divisors (see below), whose sum is σ = 126021984. Its totient is φ = 105018300.

The previous prime is 115520051. The next prime is 115520143. The reversal of 115520141 is 141025511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115520141 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115520143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5250905 + ... + 5250926.

It is an arithmetic number, because the mean of its divisors is an integer number (31505496).

Almost surely, 2115520141 is an apocalyptic number.

115520141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

115520141 is a deficient number, since it is larger than the sum of its proper divisors (10501843).

115520141 is a wasteful number, since it uses less digits than its factorization.

115520141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10501842.

The product of its (nonzero) digits is 200, while the sum is 20.

The square root of 115520141 is about 10748.0296333793. The cubic root of 115520141 is about 487.0264747584.

Adding to 115520141 its reverse (141025511), we get a palindrome (256545652).

The spelling of 115520141 in words is "one hundred fifteen million, five hundred twenty thousand, one hundred forty-one".

Divisors: 1 11 10501831 115520141