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115200053 = 4322911699
BaseRepresentation
bin1101101110111…
…01000000110101
322000202202202122
412313131000311
5213442400203
615233045325
72566120133
oct667350065
9260682678
10115200053
115a033561
12326b6845
131ab36217
141142a753
15a1a8538
hex6ddd035

115200053 has 8 divisors (see below), whose sum is σ = 118404000. Its totient is φ = 112020048.

The previous prime is 115200047. The next prime is 115200073. The reversal of 115200053 is 350002511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 115200053 - 212 = 115195957 is a prime.

It is a super-2 number, since 2×1152000532 = 26542104422405618, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115200023) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3998 + ... + 15696.

It is an arithmetic number, because the mean of its divisors is an integer number (14800500).

Almost surely, 2115200053 is an apocalyptic number.

It is an amenable number.

115200053 is a deficient number, since it is larger than the sum of its proper divisors (3203947).

115200053 is a wasteful number, since it uses less digits than its factorization.

115200053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11971.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 115200053 is about 10733.1287609904. The cubic root of 115200053 is about 486.5762342655.

Adding to 115200053 its reverse (350002511), we get a palindrome (465202564).

The spelling of 115200053 in words is "one hundred fifteen million, two hundred thousand, fifty-three".

Divisors: 1 43 229 9847 11699 503057 2679071 115200053