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1151012114 = 2782215151
BaseRepresentation
bin100010010011011…
…0000110100010010
32222012211110210022
41010212300310102
54324124341424
6310114103442
740344304310
oct10446606422
92865743708
101151012114
1154079748a
1228157ab82
13154601975
14acc1b0b0
156b0b095e
hex449b0d12

1151012114 has 8 divisors (see below), whose sum is σ = 1973163648. Its totient is φ = 493290900.

The previous prime is 1151012099. The next prime is 1151012119. The reversal of 1151012114 is 4112101511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1151012092 and 1151012101.

It is not an unprimeable number, because it can be changed into a prime (1151012119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41107562 + ... + 41107589.

It is an arithmetic number, because the mean of its divisors is an integer number (246645456).

Almost surely, 21151012114 is an apocalyptic number.

1151012114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1151012114 is a deficient number, since it is larger than the sum of its proper divisors (822151534).

1151012114 is an equidigital number, since it uses as much as digits as its factorization.

1151012114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82215160.

The product of its (nonzero) digits is 40, while the sum is 17.

The square root of 1151012114 is about 33926.5694404843. The cubic root of 1151012114 is about 1047.9968199358.

Adding to 1151012114 its reverse (4112101511), we get a palindrome (5263113625).

The spelling of 1151012114 in words is "one billion, one hundred fifty-one million, twelve thousand, one hundred fourteen".

Divisors: 1 2 7 14 82215151 164430302 575506057 1151012114