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114013103 = 175964817
BaseRepresentation
bin1101100101110…
…11001110101111
321221112110120112
412302323032233
5213141404403
615151410235
72553044501
oct662731657
9257473515
10114013103
11593a2806
123222397b
131a80bb99
14111dbd71
15a0219d8
hex6cbb3af

114013103 has 4 divisors (see below), whose sum is σ = 114079680. Its totient is φ = 113946528.

The previous prime is 114013073. The next prime is 114013111. The reversal of 114013103 is 301310411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301310411 = 433695867.

It is a cyclic number.

It is not a de Polignac number, because 114013103 - 216 = 113947567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114013153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30650 + ... + 34167.

It is an arithmetic number, because the mean of its divisors is an integer number (28519920).

Almost surely, 2114013103 is an apocalyptic number.

114013103 is a deficient number, since it is larger than the sum of its proper divisors (66577).

114013103 is an equidigital number, since it uses as much as digits as its factorization.

114013103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66576.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 114013103 is about 10677.6918385951. The cubic root of 114013103 is about 484.8993350436.

Adding to 114013103 its reverse (301310411), we get a palindrome (415323514).

The spelling of 114013103 in words is "one hundred fourteen million, thirteen thousand, one hundred three".

Divisors: 1 1759 64817 114013103